How to delete point in extract from imacros ? Example : 3.045 => 3045 (How to Delete this point ?)
I've tried deleting using a script like this can not too
Code: Select all
'ADD !EXTRACT {{!URLCURRENT}}
'WAIT SECONDS=5
TAG POS=1 TYPE=DIV ATTR=TXT:*
SET !TIMEOUT_STEP 0
TAG POS=2 TYPE=STRONG ATTR=CLASS:* EXTRACT=TXT
WAIT SECONDS=1
'SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/./g, \'\');")
PROMPT {{!EXTRACT}}
SAVEAS TYPE=EXTRACT FOLDER=* FILE=ScrapeNumber.csv
WAIT SECONDS=0.5
Code: Select all
'ADD !EXTRACT {{!URLCURRENT}}
'WAIT SECONDS=5
TAG POS=1 TYPE=DIV ATTR=TXT:*
SET !TIMEOUT_STEP 0
TAG POS=2 TYPE=STRONG ATTR=CLASS:* EXTRACT=TXT
WAIT SECONDS=1
'SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/9./g, \'9\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/0./g, \'0\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/1./g, \'1\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/2./g, \'2\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/3./g, \'3\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/4./g, \'4\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/5./g, \'5\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/6./g, \'6\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/7./g, \'7\');")
PROMPT {{!EXTRACT}}
SET !EXTRACT EVAL("\'{{!EXTRACT}}\'.replace(/8./g, \'8\');")
PROMPT {{!EXTRACT}}
SAVEAS TYPE=EXTRACT FOLDER=* FILE=ScrapeNumber.csv
WAIT SECONDS=0.5